62f8174aa2
This PR will avoid load pullrequest.Issue twice in pull request list page. It will reduce x times database queries for those WIP pull requests. Partially fix #29585 --------- Co-authored-by: Giteabot <teabot@gitea.io>
74 lines
1.9 KiB
Go
74 lines
1.9 KiB
Go
// Copyright 2022 The Gitea Authors. All rights reserved.
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// SPDX-License-Identifier: MIT
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package util
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import (
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"cmp"
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"slices"
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"strings"
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)
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// SliceContainsString sequential searches if string exists in slice.
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func SliceContainsString(slice []string, target string, insensitive ...bool) bool {
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if len(insensitive) != 0 && insensitive[0] {
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target = strings.ToLower(target)
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return slices.ContainsFunc(slice, func(t string) bool { return strings.ToLower(t) == target })
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}
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return slices.Contains(slice, target)
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}
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// SliceSortedEqual returns true if the two slices will be equal when they get sorted.
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// It doesn't require that the slices have been sorted, and it doesn't sort them either.
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func SliceSortedEqual[T comparable](s1, s2 []T) bool {
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if len(s1) != len(s2) {
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return false
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}
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counts := make(map[T]int, len(s1))
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for _, v := range s1 {
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counts[v]++
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}
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for _, v := range s2 {
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counts[v]--
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}
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for _, v := range counts {
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if v != 0 {
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return false
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}
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}
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return true
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}
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// SliceRemoveAll removes all the target elements from the slice.
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func SliceRemoveAll[T comparable](slice []T, target T) []T {
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return slices.DeleteFunc(slice, func(t T) bool { return t == target })
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}
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// Sorted returns the sorted slice
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// Note: The parameter is sorted inline.
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func Sorted[S ~[]E, E cmp.Ordered](values S) S {
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slices.Sort(values)
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return values
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}
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// TODO: Replace with "maps.Values" once available, current it only in golang.org/x/exp/maps but not in standard library
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func ValuesOfMap[K comparable, V any](m map[K]V) []V {
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values := make([]V, 0, len(m))
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for _, v := range m {
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values = append(values, v)
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}
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return values
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}
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// TODO: Replace with "maps.Keys" once available, current it only in golang.org/x/exp/maps but not in standard library
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func KeysOfMap[K comparable, V any](m map[K]V) []K {
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keys := make([]K, 0, len(m))
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for k := range m {
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keys = append(keys, k)
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}
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return keys
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}
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